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A car has two horns having a difference ...

A car has two horns having a difference in frequency of 180 Hz. The car is approaching a stationary observer with a speed of `60 ms^(-1)`. Calculate the difference in frequencies of the notes as heard by the observer, If velocity of sound in air is `330 ms^(-1)`.

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The correct Answer is:
`220 Hz`
`Delta f=f_(0)((v)/(v-v_(S)))=180((300)/(330-60))=220Hz`
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ALLEN -WAVES AND OSCILLATIONS-Part-1(Exercise-04)[A]
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