Considering a system having two masses `m_(1)` and `m_(2)` in which first mass is pushed towards centre of mass by a distance a, the distance required to be moved for second mass to keep centre of mass at same position is :-

Options

A. `(m_(1))/(m_(2))a`
B. `(m_(1)m_(2))/(a)`
C. `(m_(2))/(m_(1))a`
D. `((m_(2)m_(1))/(m_(1) + m_(2)))a`

Answer

A

Explanation

`Deltabar(x) = (m_(1).Deltax_(1) + m_(2).Deltax_(2))/(m_(1) + m_(2))`
`rArr 0 = (m_(1)a + m_(2)Deltax_(2))/(m_(1) + m_(2))`
`rArr Deltax_(2) = -(m_(1)a)/(m_(2))`