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In the conductor opposite charges separa...

In the conductor opposite charges separated by

A

Dielectric

B

insulator

C

microscopic distance

D

large distance

Text Solution

Verified by Experts

The correct Answer is:
`n=(4pi in_(0) mg(h-R)R)/Q^(2)`
Let `n^(th)` number last drop that can entre
`(KQ^(2))/Rxxn=mg (h-R) :. N=(4pi in_(0) mg(h-R)R)/Q^(2)`
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