In a crystal, atoms are located at the position of

Options

A. maximum potential energy
B. minimum potential energy
C. zero potential energy
D. infinite potential energy

Answer

D

Explanation

At the distance of closest approach
`K_("Initial")=PE_("final")`
`1/2 mv^(2)=(Kq_(1)q_(2))/r_(0)rArr r_(0) prop 1/v^(2)`
Hence `r_(20)/r_(10)=(v_(1)/v_(2))^(2)=(v/(2v))^(2)=1/4 rArr r_(20)=r_(10)/4`