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A charge Q is place at each of the oppos...

A charge Q is place at each of the opposite corners of a square. A charge q is placed at each of the other two corners. If the net electrical force on q is zero, then `q//Q` equals:

A

`1`

B

`-1/sqrt(2)`

C

`-2sqrt(2)`

D

`-1`

Text Solution

Verified by Experts

The correct Answer is:
C

Here `vec(F)_(1)+vec(F)_(2)+vec(F)_(3)=0` …(i)
`|vec(F)_(1)+vec(F)_(2)|=(sqrt(2)KQ^(2))/a^(2)`
`|vec(F)_(3)|=(KQ^(2))/((sqrt(2)a)^(2))`
from (i)
`(sqrt(2)KQq)/a^(2)+(KQ^(2))/((sqrt(2)a)^(2))=0`
`(sqrt(2)KQq)/a^(2)=(KQ^(2))/(2a^(2))rArr Q=-2sqrt(2) q`
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