The velocity of a particle moving along x-axis is given as `v=x^(2)-5x+4` (in m`//`s) where x denotes the x-coordinate of the particle in metres. Find the magnitude of acceleration of the particle when the velocity of particle is zero?

Options

A. `0 m//s^(2)`
B. `2 m//s^(2)`
C. `3 m//s^(2)`
D. None of these

Answer

A

Explanation

For `v=0, x=1, 4` and `a=v(dv)/(dx)`
so `a|._(x=1)=0xx(dv)/(dx)=0, a|_(x=4)=0xx(dv)/(dx)=0`