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The equation of one dimensional motion o...

The equation of one dimensional motion of the particle is described in column I. At `t=0`, particle is at origin and at rest. Match the column I with the statement in Column II.
`{:(,"Column I",,,"Column II"),((A),x=(3t^(2)+2)m,,(p),"Velocity of particle at t=1s is "8 m//s),((B),v=8t m//s,,(q),"Particle moves with uniform acceleration"),((C),a=16 t,,(r),"Particle moves with variable acceleration"),((D),v=6t-3t^(2),,(s),"Particle will change its direction some time"):}`

Text Solution

Verified by Experts

The correct Answer is:
(A)-q, (B)-p, q (C)-p, r, (D)-r, s

`[A] X=3t^(2)+2rArr V=(dx)/(dt)=6t rArr a=(d^(2)x)/(dt^(2))`
`[B] V=8trArr a=(dv)/(dt)=8`
[D] For changing the direction `6t-3t^(2)=0`
`rArr t=0, 2` sec
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Knowledge Check

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