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The graph between the displacement x and...

The graph between the displacement x and time t for a particle moving in a straigh lin ais shown in figure. During the internal OA,AB,BC and CD, the acceleration of the particle is:

A

`OA=+, AB=0, BC=+, CD=+`

B

`OA=-, AB=0, BC=+, CD=0`

C

`OA=+, AB=0, BC=-, CD=+`

D

`OA=-, AB=0, BC=0, CD=+`

Text Solution

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The correct Answer is:
D

`a=(d^(2)x)/(dt^(2))=` change in velocity w.r.t the time
For `OA rarr` velocity decreases so a is negative
For `AB rarr` velocity constant so a is zero.
For `BC rarr` velocity constant so a is zero
For `CD rarr` velocity increases so a is positive.
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