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For a body in circular motion with a con...

For a body in circular motion with a constant angular velocity, the magnitude of the average acceleration over a period of half a revolution is … times the magnitude of its instantaneous acceleration.

A

`2/pi`

B

`pi/2`

C

`pi`

D

`2`

Text Solution

Verified by Experts

The correct Answer is:
A
`omega=` constant, `a_(T)=0`
`[(2omega^(2)rx)/pi, omega=(2pi)/T, T/2=pi/omega]`
`a_(av)=(2omegaR)/(pi//omega)=(2omega^(2)R)/pi, a_("inst")=omega^(2)R`
So radio `=a_(av)/a_("inst")=2/pi`
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