Assertion: A projectile is thrown with an initial velocity of `(a hati+bhatj)m//sec`. If range of projectile is maximum then a=b.
Reason: In projectile motion, angle of projection is equal to `45^(@)` for maximum rang econdition.

Options

A. Statement-I is true, Statement-II is true, Statement-II is correct explanation for Statement-I
B. Statement-I is true, Statement-II is true, Statement-II is NOT a correct explanation for Statement-I
C. Statement-I is true, Statement-II is false
D. Statement-I is false, Statement-II is true.

Answer

A

Explanation

For max. range `((u^(2) sin 2theta)/g)`, the projection angle `(theta)` should be `45^(@)`
So initial velocity `ai+bjrArr tan 45^(@)=b/arArr a=b`