Home
Class 11
PHYSICS
Assertion: A projectile is thrown with a...

Assertion: A projectile is thrown with an initial velocity of `(a hati+bhatj)m//sec`. If range of projectile is maximum then a=b.
Reason: In projectile motion, angle of projection is equal to `45^(@)` for maximum rang econdition.

A

Statement-I is true, Statement-II is true, Statement-II is correct explanation for Statement-I

B

Statement-I is true, Statement-II is true, Statement-II is NOT a correct explanation for Statement-I

C

Statement-I is true, Statement-II is false

D

Statement-I is false, Statement-II is true.

Text Solution

Verified by Experts

The correct Answer is:
A
For max. range `((u^(2) sin 2theta)/g)`, the projection angle `(theta)` should be `45^(@)`
So initial velocity `ai+bjrArr tan 45^(@)=b/arArr a=b`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    ALLEN |Exercise Comprehension#1|3 Videos

  • KINEMATICS

    ALLEN |Exercise Comprehension#2|5 Videos

  • KINEMATICS

    ALLEN |Exercise EXERCISE-03|6 Videos

  • ERROR AND MEASUREMENT

    ALLEN |Exercise Part-2(Exercise-2)(B)|22 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN |Exercise BEGINNER S BOX-7|8 Videos

Similar Questions

Explore conceptually related problems

Statement-I : A projectile is thrown with an initial velocity of (ahat(i)+bhat(j)) m//s . If range of projectile is maximum then a=b . Statement-II : In projectile motion, angle of projection is equal to 45^(@) for maximum range condition.

A projectile is thrown with an initial velocity of (a hati +b hatj) ms^(-1) . If the range of the projectile is twice the maximum height reached by it, then

A particle is projected from ground with initial velocity 3hati + 4hatj m/s. Find range of the projectile :-

Maximum range of projectile depend on angle of projectile.

The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is .

A projectile is given an initial velocity hati+2 hatj .The cartesin equation of its path is (g=10ms^(-2))

When angle of projection is …... Range of projectile will be maximum.

A projectile fired with initial velocity u at some angle theta has a range R . If the initial velocity be doubled at the same angle of projection, then the range will be

Assertion: In projectile motion, the vertical velocity of the particle is continoulsy decreased during its ascending motion. Reason: In projectile motion downward constant acceleration is present in vertical direction.

A projectile is thrown with a velocity of 50ms^(-1) at an angle of 53^(@) with the horizontal Choose the incorrect statement

Home
Profile