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For the velocity -time graph shown in fi...

For the velocity -time graph shown in figure, in a time interval from `t=0` to `t=6 s`, match the following:

`{:(,"Column I",,,"Column II"),((A),"Change in velocity",,(p),-5//3 SI "unit"),((B),"Average acceleration",,(q),-20 SI "unit"),((C),"Total displacement",,(r),-10 SI "unit"),((D),"Acceleration ay t=3s",,(s),-5 SI "unit"):}`

Text Solution

Verified by Experts

The correct Answer is:
(A)-r, (B)-p, (C)-r (D)-s
At `t=0, v(0)=10 m//s, t=0, v(6)=0`
Change `v(6)-v(0), Deltav=0-10=-10 m//s`

Average acceleration
`=("charge in velocity")/("time")=(-10)/6=(-5)/3 m//s^(2)`
Average velocity `=("Displacement")/("time interval")`
Total displacement = Area of `Delta's` (with +ve or -ve)
`=1/2xx2xx10-1/2xx4xx10=-10 m` (units)
`:.` Average velocity `=(-10)/6=-(-5)/3 m//s`
`a(3)=` slope of line which exist at `t=0 I_(0) t=4`
`a= tan theta=(-10)/2 =-5`
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