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A body moving with uniform acceleration, covers a distance of `20` m in the `7^(th)` second and `24 m` in the `9^(th)` second. How much shall it cover in `15^(th)` second?

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The correct Answer is:
`36 m`
`S_(n)=u+a/2 (2n-1)` by putting the value of `n=7` and 9, find the value of u & `a, u=7 m//s` & `a=2 m//s^(2)`.
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