A particle is moving in a circular orbit with a constant tangential acceleration. After a certain time t has elapsed after the beginning of motion, the between the total acceleration a and the direction along the radius r becomes equal to `45^(@)`. What is the angular acceleration of the particle.

Answer

`1/t^(2)`

Explanation

`a_(t)=ar, alphar=omega^(2)r, alpha=alpha^(2)t^(@)rArr alpha=1/t^(2)`