The temperature of an iron piece is heated from `30^@ C "to" 90^@ C`. What is the change in its temperature on the fahrenheit scale and on the kelvin scale?

Explanation

`Delta C=90^(@)-30^(@) = 60^(@)C`
Temperature difference on Fahrenheit Scale `DeltaF =(9)/(5)DeltaC =(9)/(5)(60^(@)C)=108^(@)F`
Temperature difference on Kelvin Scale ` DeltaK= DeltaC = 60K`