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Total radiations incident on body = 400 ...

Total radiations incident on body = `400 J`, `20%` radiation reflected and `120` J absorbs. Then find out `%` of transmittive power

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` Q=Q_(t)+Q_(r) + Q_(a) implies 400=80+120+Q_(t)implies Q_(t)=200 " "` So `%` of transmittive power is `50%`
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