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Find rms speed of oxygen molecules at te...

Find `rms` speed of oxygen molecules at temperature `27^(@)C`.

Text Solution

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Temperature , `T= 27^(@)C implies 273+27 = 300K,`
Molecular weight of oxygen =`32xx10^(-3)` kg and ` R=8.31J mol^(-1)K^(-1)`
rms velocity is `v_("rms") = sqrt((3RT)/(M))= sqrt((3xx8.31xx300)/(32xx10^(-3)))= 483.5 ms^(-1)`
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