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A gram molecule of a gas at 127^(@)C exp...

A gram molecule of a gas at `127^(@)C` expands isothermally until its volume is doubled. Find the amount of work done and heat absorbed.

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n=`2` , `T=127+273 = 400K, (V_(2))/(V_(1)) = 2 `
From formula `" "` `W = 2.3026 nRT "log"_(10) (V_(2))/(V_(1)) = 2.3026xx2xx8.3xx400xx"log"_(10)2`
` = 2.3026 xx2xx8.3xx400xx0.3010 approx 4.6 xx 10^(3)J`
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