In Newton's law of cooling `(d theta)/(dt)=-k(theta-theta_(0))` the constant `k` is proportional to .

Options

A. (a)`A`, surface area of the body
B. (b)`S`, specific heat of the body
C. (c)`(1)/(m)`, m being mass of the body
D. (d)e, emissity of the body

Answer

A, C

Explanation

`(dQ)/(dt) = esigmaA(theta^(4)-theta_(0)^(4)) approx(3esigmaAtheta_(0)^(3))Deltatheta`
`(dQ)/(dt) = esigmaA(theta^(4)-theta_(0)^(4)) approx(3esigmaAtheta_(0)^(3))Deltatheta`