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Pressure versus temperature graph of an ...

Pressure versus temperature graph of an ideal gas is shown in figure. Density of the gas at point A is `rho_(0)`. Density at B will be

A

`(3)/(4)rho_(0)`

B

`(3)/(2)rho_(0)`

C

`(4)/(3)rho_(0)`

D

`2rho_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
Ideal gas equation `P = (rho)/(M)RT`
For state `A` :
`P_(0) = (rho_(0))/(M) RT_(0)`
For state `B` `3P_(0) = (rho)/(M) R2T_(0) implies rho = (3)/(2)rho_(0)`
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