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The thermal capacity of 40 g of aluminiu...

The thermal capacity of 40 g of aluminium (specific heat `=0.2 cal//gm^(@)C`)

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The correct Answer is:
A, C
`C_(P)-C_(V) =R, M (0.25 - 0.15) = 2[M`= molar mass]
` implies M = (2)/(0.05) = 40`g
`(C_(P))/(C_(V)) = gamma = (0.2)/(0.15) = (4)/(3) =1 + (2)/(f)`
`implies` f = degrees of freedom = `6`
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