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A simple pendulum has time period 2s. Th...

A simple pendulum has time period `2s`. The point of suspension is now moved upward accoding to relation `y = (6t - 3.75t^(2))m` where `t` is in second and y is the vertical displacement in upward direction. The new time period of simple pendulum will be

A

`2s`

B

`1s`

C

`4s`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`T_(1) = 2s = 2pisqrt((l)/(g)), T_(2) = 2pisqrt((l)/(g'))` where `g = g + (d^(2)y)/(dt^(2)) = 10 - 7.5 = 2.5 = (g)/(4) rArr T_(2) = 2pisqrt((l)/(g//4)) = 2 xx 2 = 4s`
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