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Two bodies performing S.H.M. have same a...

Two bodies performing `S.H.M.` have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is

A

(a)`(11)/(6)pi`

B

(b)`pi`

C

(c)`(5)/(3)pi`

D

(d)`(3)/(5)pi`

Text Solution

Verified by Experts

The correct Answer is:
C


`cos theta = (A//2)/(A) = 1/2 rArr theta = (pi)/(3)`
Total ohase difference between them
`phi = 2theta + pi = (5pi)/(3)`
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