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Block A in the figure is released from t...

Block `A` in the figure is released from the rest when the extension in the spring is `x_(0)`. The maximum downward displacement of the block will be `:`

A

`(Mg)/(2k)-x_(0)`

B

`(Mg)/(2k)+x_(0)`

C

`(2Mg)/(k)-x_(0)`

D

`(2Mg)/(k)+x_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
For maximum displacement
`Mg(x) = 1/2k(2x)^(2) rArr x = (Mg)/(2k) rArr x = (mg)/(2k) - x_(0)`
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