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A pendulum is suspended in a lift and it...

A pendulum is suspended in a lift and its period of oscillation when the lift is stationary is `T_(0)`. What must be the accleraion of the lift for the period of oscillation of the pendulum to be `T_(0)//2`?

A

`2g` downward

B

`2g` upward

C

`3g` downward

D

`3g` upward

Text Solution

Verified by Experts

The correct Answer is:
D
`T_(0) = 2pisqrt((l)/(g_(eff)))`….(i)
Now `(T_(0))/(2) = 2pisqrt((l)/(g + a))`….(ii)
`rArr (g +a )/(g) = 4 rArr a = 3g` (upwards)
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