The frequency of a simple pendulum is `n` oscillations per minute while that of another is `(n + 1)` oscillations per minute. The ratio of length of first second is-

Options

A. `(n)/(n+1)`
B. `(n+(1)/(n))^(2)`
C. `((n+1)/(n))^(2)`
D. `((n)/(n+1))^(2)`

Answer

C

Explanation

`T = 1/f = 2pisqrt((l)/(g)) rArr f = (1)/(2pi) sqrt((g)/(l))`
`(f_(1))/(f_(2)) = sqrt((l_(2))/(l_(1))) rArr ((n)/(n+1))^(2) = (l_(2))/(l_(1)) rArr = (l_(1))/(l_(2)) = ((n+1)/(n))^(2)`