The distance between the point of suspension and the centre of gravity of a compound pendulum is `l` and the radius of gyration about the horizontal axis through the centre of gravity is `k`, then its time period will be

Options

A. `2pisqrt((l+k)/(g))`
B. `2pisqrt((l^(2)+k^(2))/(lg))`
C. `2pisqrt((l+k^(2))/(g))`
D. `2pisqrt((2k)/(lg))`

Answer

B

Explanation

`T = 2pisqrt((l)/(mgl)) = 2pisqrt((l^(2) + k^(2))/(gl))`