The phase of a particle in `SHM` at time `t` is `(13pi)/(6)`. The following interference is drawn form this

Options

A. (a)the particle is at `x = a/2` and movin in `+` X-direction
B. (b)the particle is at `x = a/2` moving in `- X-`direction
C. (c)the particle is at `x = -a/2` moving in `+ X-`direction
D. (d)the particle is at `x = -a/2` moving in `- X-`direction

Answer

A

Explanation

`sin((13pi)/(6)) = sin (2pi + (pi)/(6)) = sin '(pi)/(6) = (1)/(2)`
Now `x = a sin (omegat) = a/2`