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The time period of an oscillator is 8 se...

The time period of an oscillator is `8` sec. the phase difference from `t = 2` sec to `l = 4` sec will be :-

A

(a)`pi`

B

(b)`(pi)/(2)`

C

(c)`(pi)/(4)`

D

(d)`2pi`

Text Solution

Verified by Experts

The correct Answer is:
B
`(DeltaT)/(T) = (Deltaphi)/(2pi) rArr 2/8 = (Deltaphi)/(2pi) rArr Deltaphi = pi/2`
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