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A paricle performs S.H.M. with time peri...

A paricle performs `S.H.M.` with time period `T`. The time taken by the particle to move from half the amplitude to the maximum dispalcement is

A

(a)`T/2`

B

(b)`T/4`

C

(c)`T/6`

D

(d)`T/8`

Text Solution

Verified by Experts

The correct Answer is:
C
Required time `= T/4 - T/12 = T/6`
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