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A particle of mass m excuting SHM make f...

A particle of mass `m` excuting `SHM` make `f` oscillation per second. The difference of its kinetic energy when at the centre, and when at distance x from the centre is

A

(a)`pi^(2)f^(2)x^(2)m`

B

(b)`2pi^(2)f^(2)x^(2)m`

C

(c)`(1)/(2)pi^(2)f^(2)x^(2)m`

D

(d)`f^(2)x^(2)m`

Text Solution

Verified by Experts

The correct Answer is:
B
`KE` at centre
`= 1/2 momega^(2)(A)^(2) = 1/2m4pi^(2)f^(2)A^(2)`
KE at distance `x`
`= 1/2 m4pi^(2)f^(2)(A^(2) - x^(2))`
Difference `= 1/2 m xx 4pi^(2)f^(2)x^(2) = 2pi^(2)f^(2)x^(2)m`
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