A particle is subjected to two simple harmonic motions along x and y directions according to `x=3sin100pit`, `y=4sin100pit`.

Options

A. (a)Motion of particle will be on ellipse traversing it in clockwise direction
B. (b)Motion of particle will be on a straight line with slope `4//3`
C. (c)Motion will be simple harmonic motion with amplitude `5`
D. (d)Phase difference between two motion is `pi//2`

Answer

B, C

Explanation

`x = 3 sin (100 pit), y = 4 sin (100 pit) rArr y = (4)/(3)x`
`rArr` Motion of particle will be on a strainght line with slope `4//3`
As `r = sqrt(x^(2) + y^(2)) = 5 sin (100 pit)`
so motion of particle will be SHM with amplitude `5`.