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A photon of energy 12.09 eV is completel...

A photon of energy `12.09 eV` is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of excited state is

A

4

B

5

C

3

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
Energy difference in hydrogen atom `= 13.6 - (13.6)/(n^(2)) = 12.09 rArr n^(2) ~~ 9 rArr n = 3`
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