Let `K_(1)` be the maximum kinetic energy of photoelectrons emitted by a light of wavelength `lambda_(1)` and `K_(2)` corresponding to `lambda_(`2). If `lambda_(1) = 2lambda_(2)`, then

Options

A. `2K_(1) = K_(2)`
B. `K_(1) = 2K_(2)`
C. `K_(1) lt (K_(2))/(2)`
D. `K_(1) gt 2K_(2)`

Answer

C

Explanation

`(K_(2))/(K_(1)) = ((hc)/(lambda_(2)) - phi)/((hc)/(lambda_(1)) - phi) = (2((hc)/(lambda_(2)) - phi))/(((hc)/(lambda_(2)) - 2phi)) rArr K_(1) lt (K_(2))/(2)`