The muon has the same change as an electron but a mass that is `207` times greater. The negetively charged muon can bind to a prtoton to form a new type of hydrogen atom. How does the binding energy `E_(Bmu)`, of the muon the ground state of muonic hydrogen atom campare with the binding energy `E_(Be')` of an electron in the ground state of a conventional hydrogen atom?

Options

A. `|E_(Bmu)| = |E_(Be)|`
B. `|E_(Bmu)|~~ 100 |E_(Be)|`
C. `|E_(Bmu)|~~|E_(Be)|//107`
D. `|E_(Bmu)|=207|E_(Be)|`

Answer

D

Explanation

Binding energy `prop` charge
`|(E_(Bmu))/(E_(Be))| = -(207e)/(e)`