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If N(t) = N(o)e^(lambdat) then number of...

If `N_(t) = N_(o)e^(lambdat)` then number of disintefrated atoms between `t_(1)` to `t_(2) (t_(2) gt t_(1))` will ve :-

A

`N_(o)[e^(lambdat_(2))-e^(lambdat_(3))]`

B

`N_(o)[-e^(lambdat_(2)) - e^(-lambdat_(1))]`

C

`N_(o)[e^(-lambdat_(1)) - e^(-lambdat_(2))]`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaN? = N_(1) rarr N_(2) = N_(0)[e^(-lambdat_(1)) - e^(-lambdat_(2))]`
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