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Atomic weight of a radioactive element i...

Atomic weight of a radioactive element is `M_(W)` gm. Radioactivity of m gm of its mass is :-
(`N_(A) = ` Avogardro number, `lambda` = decay constant)

A

`N_(A)lambda`

B

`[(N_(A))/(M_(W))m]lambda`

C

`[(N_(A))/(m)]lambda`

D

`[(N_(A))/(m)M_(w)]lambda`

Text Solution

Verified by Experts

The correct Answer is:
B
`R = lambdaN = lambda[(m)/(M_(w)) N_(A)]`
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