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In the adjacent figure ABCD is a quadria...

In the adjacent figure ABCD is a quadriateral & `/_ADB = /_BCA = 22^(@)`, then `/_BCD +/_BAD` is-

A

`66^(@)`

B

`90^(@)`

C

`132^(@)`

D

`180^(@)`

Text Solution

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The correct Answer is:
A
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