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A circular arc of length pi cm. Find ang...

A circular arc of length `pi` cm. Find angle subtended by it at the centre in radian and degree.

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Comparing this equation with standard quadration `ax^(2)+bx+c=0`,
we have `a=2, b=-1, c=-3`
Now from, `x=(-b+-sqrt(b^(2)-4ac))/(2a), x=(-(-1)+-sqrt((-1)^(2)-4(2)(-3)))/(2(2))`
`x=(1+-sqrt(1+24))/(4)=(1+-5)/(4)rArr x_(1)=(+6)/(4)=3/2` and `x_(2)=-1`
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Knowledge Check

  • A circular wire of radius 7 cm is cut and arrange on the diameter of a circle with radius 12 cm. The angle subtended by it at the centre of the circle is …………

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    B
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  • In a circle with radius 3 cm an arc of length 1 cm subtends an angle of measure ……… at the centre of the circle.

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    2 Radian
    B
    3 Radian
    C
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    D
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