Let catching point be `(x_(1), y_(1))` then, `y_(1)-x_(1)=0` and `x_(1)^(2)+y_(1)^(2)=8` Therefore, `2x_(1)^(2)=8 rArr x_(1)^(2)=4 rArr x_(1)=+-2`, So possible points are `(2, 2)` and `(-2, -2)`.
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