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In quadratic equation ax^(2)+bx+c=0, if ...

In quadratic equation `ax^(2)+bx+c=0`, if discriminant `D=b^(2)-4ac`, then roots of quadratic equation are:

A

`1/5`

B

`2/5`

C

`4/5`

D

`3/5`

Text Solution

Verified by Experts

The correct Answer is:
C
For maximum/ minimum value `(dy)/(dx)=0rArr 5(2x)-2(1)+0=0rArr x=1/5`
Now at `x=1/5, (d^(2)y)/(dx^(2))=10` which is positive so minima at `x=1/5`
Therefore `y_("min")=5(1/5)^(2)-2(1/5)+1=4/5`
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