The mass m of a body moving with a velocity v is given by `m=m_(0)/sqrt(1-v^(2)/c^(2))` where `m_(0)` = rest mass of body `=10 kg` and c = speed of light `=3xx10^(8) m//s`. Find the value of m at `v=3xx10^(7) m//s`
A
x-coordinate
B
y-coordinate
C
Both x and y-coordinate
D
Data insufficient
Text Solution
Verified by Experts
The correct Answer is:
B
`12y=x^(3)rArr 12dy=3x^(2)dx rArr (dy)/(dt)=(x/2)^(2)((dx)/(dt))` Therefore for `(x/2)^(2) gt 1` or `x gt 2`, y-coordinate changes as faster rate.
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