Find sum of first n squared natural numbers i.e. `1^(2)+2^(2)+3^(2)+....+n^(2)`.
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The correct Answer is:
A-P,Q,R,S; B-Q, R; C-P,S; D-P, S
For (A) : `vec(F)=-2xyz hat(i)-x^(2)zhat(j)-x^(2)yhat(k) rArr F_(x)=0, F_(y)=0, F_(z)=0, U=0` For (B): `vec(F)=-2xhat(i)-zhat(j)-yhat(k)rArr F_(x) ne 0, F_(y)=0, F_(z)=0, U ne 0` For (C) : `vec(F)=-2x(y+z)hat(i)-x^(2)hat(j)-x^(2)hat(k)rArr F_(x)=0, F_(y) ne 0, F_(z) ne 0, U=0` For (D) : `vec(F)=-2xy hat(i)-x^(2)hat(j)-hat(k)rArr F_(x)=0, F_(y) ne 0, F_(z) ne 0, U=0`
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