Two forces of magnitudes 3N and 4N respectively are acting on a body. Calculate the resultant force if the angle between them is : (i) `0^(@)` (ii) `180^(@)` (iii) `90^(@)`
Two forces of magnitudes 3N and 4N are acted on a body. The ratio of magnitude of minimum and maximum resultant force on the body is
Two forces, each of magnitude F have a resultant of the same magnitude F. The angle between the two forces is
Three forces of magnitudes 2N, 3N and 6N act at corners of a cube along three sides as shown in figure. Find the resultant of these forces in N.
The maximum and minimum resultant of two forces acting at a point are 10N and 6N respectively. If each force is increased by 3N, find the resultant of new forces when acting at a paint at an angle of 90^(@) with each-other :-
A block is applied two forces of magnitude 5N each. One force is acting towards East and the other acting along 60^(@) North of East. The resultant of the two forces (in N) is of magnitude :-
Square of the resultant of two forces of equal magnitude is equal to three times the product of their magnitude. The angle between them is
The greatest & the least magnitude of the resultant of two forces of constant magnitudes are P & Q respectively. If the forces act at an angle 2 alpha , then prove that the magnitude of their resultant is given by sqrt(P^(2) cos^(2) alpha+Q^(2) sin^(2) alpha) .
The resultant of two forces,one double the other in magnitude,is perpendicular to the smaller of the two forces.The angle between the two forces is
What is the magnitude of the resultant force of the forces (1, 2, -1) and (-3, 0, 2) ?
