Home
Class 12
PHYSICS
Two forces each numerically equal to 5N ...

Two forces each numerically equal to 5N are acting on each other and angle between them is `60^(@)` , then find resultant of these two vectors.

Text Solution

Verified by Experts

The correct Answer is:
B
Average velocity `=(underset(0)overset(25)intvdt)/(25-0)=("Area of v-t graph between t=0 to t=25 s")/25=1/25[((25+10)/2)(20)]=14 m//s`
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Two force each numerically equal to 10 dynes are acting as shown in the figure, then find resultant of these two vectors.

Two force each numerically equal to 10 dynes are acting as shown in the figure, then find resultant of these two vectors.

100 coplanar forces each equal to 10 n act on a body. Each force makes angle pi//50 with the preceding force. What is the resultant of the forces.

A block is applied two forces of magnitude 5N each. One force is acting towards East and the other acting along 60^(@) North of East. The resultant of the two forces (in N) is of magnitude :-

Two forces, each of magnitude F have a resultant of the same magnitude F. The angle between the two forces is

Two vectors vecP and vecQ that are perpendicular to each other are :

The two adjacent sides of a cyclic quadrilateral are 2a n d5 and the angle between them is 60^0dot If the area of the quadrilateral is 4sqrt(3) , find the remaining two sides.

Two equal forces are acting at a point with an angle of 60^(@) between them. If the resultant force is equal to 60sqrt(3)N , The magnitude of each force is :-

Two equal forces are acting at a point with an angle of 60^(@) between them. If the resultant force is equal to 40sqrt(3)N , The magnitude of each force is :-

Two equal forces are acting at a point with an angle of 60^(@) between them. If the resultant force is equal to 20sqrt(3)N , The magnitude of each force is :-