Find out the angle made by `(hati+hatj)` vector from X and Y axes respectively.
Text Solution
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For side AB : `m=(1-0)/(0-(-2))=1/2, c=1rArry=1/2x+1` For side BC : `m=(2-0)/(0-1)=-2, c=1rArr y=-2x+1` For side CD : `m=(0-(-1))/(2-0)=1/2, c=-1rArry=1/2x-1` For side DA : `m=(-1-0)/(0-(-2))=-1/2, c=-1rArry=-1/2x-1`
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