Find out the angle made by `vecA=hati+hatj+hatk` vector from X,Y and Z axes respectively.
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intercept is `c=2`. Now the required equation is `y=3/5x+2`
Linear variation is represented by a linear equation of the form `y=mx+c`. To repersent the function on graph we have to join two points whose coordinates are `(x_(1), y_(1))` and `(x_(2), y_(2))` i.e. `(0, 2)` and `(10, 8)`. Slope of the line is `m=(y_(2)-y_(1))/(x_(2)-x_(1))=(8-2)/(10-0)=3/5`
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