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Three vectors vecA,vecB and vecC are suc...

Three vectors `vecA,vecB` and `vecC` are such that `vecA=vecB+vecC` and their magnitudes are in ratio 5:4:3 respectively. Find angle between vector `vecA` and `vecC`

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The correct Answer is:
3
`(veca+2vecb).(5veca-4vecb)=0rArr 5a^(2)+10veca.vecb-8vecb^(2)-4veca.vecbrArr -3+6veca.vecb=0`
`rArr ab cos theta=3/6 rArr cos theta=1/2=theta=pi/3rArr k=3`
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