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The kinetic energy of a particle of mass...

The kinetic energy of a particle of mass m moving with speed v is given by `K=(1)/(2)mv^(2)`. If the kinetic energy of a particle moving along x-axis varies with x as `K(x)=9-x^(2)`, then The region in which particle lies is :

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The correct Answer is:
D
`[(ab)/(RT)]=[(PV^(2))/(PV)]=[V^(2)]=M^(0)L^(6)T^(0)`
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