The heat generated in a cirucit is dependent upon the resstance, current and time for which the current is flown. If the error in measuring the above are as `1%,2%` and `1%` the maximum error in measuring heat will be

Answer

`Q^(2)/(mpi in_(0)V^(2))`

Explanation

Conservation of momentum (COM)
`0+mV=(m+m)V_(f), V_(f)=V/2`
COME: `1/2 mV^(2)=1/2 m(V/2)^(2)+1/2 m (V/2)^(2)+(Kq^(2))/d`
`d=Q^(2)/(pim in_(0) v^(2))`