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A man walks for some time 't' with veloc...

A man walks for some time 't' with velocity(v) due east. Then he walks for same time 't' with velocity (v) due north. The average velocity of the man is:-

A

`(2v_(0)^(2))/(g)`

B

`v_(0)^(2)/g`

C

`v_(0)^(2)/(2g)`

D

`v_(0)^(2)/(4g)`

Text Solution

Verified by Experts

The correct Answer is:
D
Position of the cable at the mx. Height point.
`H=((V_(0) sin 45)^(2))/(2g)=V_(0)^(2)/(4g)`
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